The force required to stretch a steel wire of $1\,c{m^2}$ cross-section to $1.1$ times its length would be $(Y = 2 \times {10^{11}}\,N{m^{ - 2}})$
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(a) $F = A \times Y \times {\rm{strain}}$=$1 \times {10^{ - 4}} \times 2 \times {10^{11}} \times 0.1 = 2 \times {10^6}N$
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