The function f(x) = 2 x^3 - 3 x^2 + 90x + 174 is increasing in th… - Vidyadip

MCQ

The function $f(x) = 2{x^3} - 3{x^2} + 90x + 174$ is increasing in the interval

A
${1 \over 2} < x < 1$
B
${1 \over 2} < x < 2$
C
$3 < x < {{59} \over 4}$
✓
$ - \infty < x < \infty $

✓

Answer

Correct option: D.

$ - \infty < x < \infty $

d
(d) $f'\,(x) = 6\,({x^2} - x + 15) > 0\,\forall \,x$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6. Application of derivatives→6. Application of derivatives — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

$\int_0^{\pi /3} {\cos 3x\,dx = } $

If the function $f(x)=\left\{\begin{array}{ll}k_{1}(x-\pi)^{2}-1, & x \leq \pi \\ k_{2} \cos x, & x>\pi\end{array}\right.$ is twice differentiable, then the ordered pair $\left( k _{1}, k _{2}\right)$ is equal to

$\int \frac{d x}{e^x+e^{-x}}=$ _________ + C.

Let $f'(x) > 0$ and $g'(x) < 0$ for all $x \in R$ then

Find values of $\mathrm{k}$ if area of triangle is $4$ square units and vertices are $(-2,0),(0,4),(0, \mathrm{k})$

The number of solutions for the equation $ 2\sin ^{ -1 }{ \sqrt { { \text{x} }^{ 2 }- \text{x}+1 } } +\cos ^{ -1 }{ \sqrt { { \text{x} }^{ 2 }- \text{x} } } =\frac { 3\pi }{ 2 }$ is:

1
2
3
Infinite

The point of intersection of the lines $\frac{{x + 1}}{3} = \frac{{y + 3}}{5} = \frac{{z + 5}}{7}$ and $\frac{{x - 2}}{1} = \frac{{y - 4}}{3} = \frac{{z - 6}}{5}$is

Choose the correct answer:
Area of the region bounded by the curve y² = 4x, y-axis and the line y = 3 is:

2
$\frac94$
$\frac93$
$\frac92.$

If $AB = C$, then matrices $A,B,C$are

The determinant $\left| {\,\begin{array}{*{20}{c}}a&b&{a - b}\\b&c&{b - c}\\2&1&0\end{array}\,} \right|$ is equal to zero if $a,b,c$ are in