MCQ
The largest no. of molecules are in
- ✓$36\,g\,H_2O$
- B$28\,g\,CO$
- C$46\,g\,C_2H_5OH$
- D$54\,g\,N_2O_5$
$C_2H_5OH = 1\,mole, N_2O_5 = 1/2\,mole$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$N{O_{\left( g \right)}} + \frac{1}{2}{O_2}_{\left( g \right)} \rightleftharpoons N{O_2}_{\left( g \right)}$
Given : $\Delta G^o_f (NO_2) = 52.0\, KJ/mole$
$\Delta G^o_f (NO) = 87.0\, KJ/mole$
$\Delta G^o_f (O_2) = 0\, KJ/mole$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,OH\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_2}Cl}\limits_1 $ $\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_3}}\limits_2 $ $\mathop {\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}C\mathop C\limits^ + {{(C{H_3})}_2}} \\
{|\,\,\,\,} \\
{Cl\,\,\,}
\end{array}}\limits_3 $ $\mathop {{{(C{H_3})}_2}\mathop C\limits^ + CH{{(C{H_3})}_2}}\limits_4 $