The length of a sonometer wire tuned to a frequency of $250 Hz$ is $0.60$ metre. The frequency of tuning fork with which the vibrating wire will be in tune when the length is made $0.40$ metre is .... $Hz$
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(b) ${n_1}{l_1} = {n_2}{l_2} \Rightarrow 250 \times 0.6 = {n_2} \times 0.4 \Rightarrow {n_2} = 375$
$ \Rightarrow {n_2} = 375\,Hz$
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