A galvanometer having a resistance of $9\, ohm$ is shunted by a wire of resistance $2\, ohm$. If the total current is $1\, amp$, the part of it passing through the shunt will be ............ $amp$
AIPMT 1998, Medium
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${i_g}S = (i - {i_g})G$
${i_g}(S + G) = iG$
$\frac{{{i_g}}}{i} = \frac{G}{{S + G}} = \frac{9}{{2 + 9}} \approx 0.8$
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