The magnetic field existing in a region is given by $\overrightarrow{\mathrm{B}}=0.2(1+2 \mathrm{x}) \hat{\mathrm{k} T}$. A square loop of edge $50 \mathrm{~cm}$ carrying $0.5 \mathrm{~A}$ current is placed in $x-y$ plane with its edges parallel to the $x-y$ axes, as shown in figure. The magnitude of the net magnetic force experienced by the loop is___________. $\mathrm{mN}$.
JEE MAIN 2024, Diffcult
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Force on segment parallel to $\mathrm{x}$-axis will cancel each other. Hence $F_{\text {net }}$ will be due to portion parallel to $y$-axis.
$F=0.5 \times 0.5 \times 6 \times 0.2-0.5 \times 0.5 \times 0.2 \times 5$
$=0.5 \times 0.5 \times 0.2$
$=0.25 \times 0.2$
$=50 \times 10^{-3} \mathrm{~N}$
$=50 \mathrm{mN}$
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