The magnetic field on the axis of a circular loop of radius $100\,cm$ carrying current $I=\sqrt{2}\,A$, at point $1\,m$ away from the centre of the loop is given by
NEET 2022, Medium
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$B _{ A }= B _0 \sin ^3 \theta$
$=\frac{\mu_0 i }{2 R } \times \sin ^3 \theta$
$=\frac{4 \pi \times 10^{-7} \times \sqrt{2}}{2 \times 1} \times\left(\frac{1}{2 \sqrt{2}}\right)$
$B _{ A }=3.14 \times 10^{-7}\,T$
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