c (c) Manganin or constantan are used for making the potentiometer wire.
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Two cells are connected in opposition as shown. Cell $\mathrm{E}_1$ is of $8 \mathrm{~V}$ emf and $2 \ \Omega$ internal resistance; the cell $E_2$ is of $2 \mathrm{~V}$ emf and $4\ \Omega$ internal resistance. The terminal potential difference of cell $\mathrm{E}_2$ is:
When current supplied by a cell to a circuit is $0.3 \,A$, its terminal potential difference is $0.9 \,V$. When the current supplied becomes $0.25 \,A$, its terminal potential difference becomes $1.0 \,V$. The internal resistance of the cell is ............ $\Omega$
For a wire $\frac{R}{l}=\frac{1}{2}$ and length of wire is $l=5\, cm .$ If potential difference $1\, V$ is applied across it, current through wire will be: $( R =$ Resistance $)$ (in $A$)
The electromotive force of a primary cell is $2\, volts$. When it is short-circuited it gives a current of $4$ amperes. Its internal resistance in $ohms$ is
A wheatstone bridge is used to determine the value of unknown resistance $X$ by adjusting the variable resistance $Y$ as shown in the figure. For the most precise measurement of $X$, the resistances $P$ and $Q$:
In circuit shown below, the resistances are given in $ohms$ and the battery is assumed ideal with emf equal to $3\, volt$. The voltage across the resistance $R_4$ is ................. $V$