MCQ
The maximum amount of $BaS{O_4}$ precipitated on mixing equal volumes of $BaC{l_2}$ $(0.5\,\, M)$ with ${H_2}S{O_4}$ $(1\,\,M)$ will correspond to .................$\mathrm{M}$
- ✓$0.5$
- B$1$
- C$1.5$
- D$2$
✓
Answer
Correct option: A.
$0.5$
a
(a) $BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$
(a) $BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$
One mole of $BaC{l_2}$ reacts with one mole of ${H_2}S{O_4}$.
Hence $0.5$ mole will react with $0.5$ mole of ${H_2}S{O_4}$ i.e. $BaC{l_2}$ is the limiting reagent.
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