The maximum potential energy of a block executing simple harmonic motion is $25\,J$. A is amplitude of oscillation. At $A / 2$, the kinetic energy of the block is $...............$
JEE MAIN 2023, Easy
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$u _{\max }=\frac{1}{2} m \omega^2 A ^2=25\,J$
$KE \text { at } \frac{ A }{2}=\frac{1}{2} mv _1^2=\frac{1}{2} m \omega^2\left( A ^2-\frac{ A ^2}{4}\right)$
$KE =\frac{1}{2} m \omega^2 \frac{3 A ^2}{4}=\frac{3}{4}\left(\frac{1}{2} m \omega^2 A ^2\right)$
$KE =\frac{3}{4} \times 25=18.75\,J$
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