MCQ
The molecular weight of a gas is $44$. The volume occupied by $2.2\, g$ of this gas at $0^\circ C$ and $2\, atm.$ pressure will be ....... $lit$
- ✓$0.56$
- B$1.2$
- C$2.4$
- D$5.6$
✓
Answer
Correct option: A.
$0.56$
a
$PV = mrT$$ = m\left( {\frac{R}{M}} \right)T$
$PV = mrT$$ = m\left( {\frac{R}{M}} \right)T$
$\Rightarrow$ $V = \left( {\frac{m}{M}} \right)\frac{{RT}}{P}$=$\left( {\frac{{2.2}}{{44}}} \right) \times \frac{{8.31 \times (273 + 0)}}{{2 \times (1 \times {{10}^5})}}$
= $5.67 \times {10^{ - 4}}{m^3}$ $= 0.56 \; liter$
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