MCQ
The number of molecules in $16\, g$ of methane is
- A$3.0 \times {10^{23}}$
- ✓$6.02 \times {10^{23}}$
- C$\frac{{16}}{{6.02}} \times {10^{23}}$
- D$\frac{{16}}{{3.0}} \times {10^{23}}$
✓
Answer
Correct option: B.
$6.02 \times {10^{23}}$
b
(b) $16\,gm$ of $C{H_4}$= $1$ mole $ = 6.023 \times {10^{23}}$ molecules.
(b) $16\,gm$ of $C{H_4}$= $1$ mole $ = 6.023 \times {10^{23}}$ molecules.
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