MCQ
The number of $N$ atoms is $681 \,g$ of $C _{7} H _{5} N _{3} O _{6}$ is $x \times 10^{21}$. The value of $x$ is $.....$ $\left( N _{ A }=6.02 \times\right.$ $10^{23}\, mol ^{-1}$ ) (Nearest Integer)
- A$6418$
- ✓$5418$
- C$5118$
- D$5948$
✓
Answer
Correct option: B.
$5418$
b
M.M. of $C _{7} H _{5} N _{3} O _{6}$ is $84+5+42+96=227$
M.M. of $C _{7} H _{5} N _{3} O _{6}$ is $84+5+42+96=227$
$n _{ C _{7} H _{5} N _{3} O _{6}}=\frac{681}{227}=3$
$n _{ N }=\frac{681}{227} \times 3=9 mol$
no. of $N$ atoms $=9 \times 6.02 \times 10^{23}$
$=5418 \times 10^{21}$
$\therefore$ The answer is $5418 .$
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