MCQ
The number of oxygen atoms in $4.4\, g$ of $C{O_2}$ is approx........ $\times {10^{23}}$.
- ✓$1.2$
- B$0.6$
- C$6$
- D$12$
✓
Answer
Correct option: A.
$1.2$
a
(a) $44\,g$ of $CO_2$ has $2 \times 6 \times {10^{23}}$ atoms of oxygen
(a) $44\,g$ of $CO_2$ has $2 \times 6 \times {10^{23}}$ atoms of oxygen
$4.4\,g$ of $CO_2$ has =$\frac{{12 \times {{10}^{23}}}}{{44}} \times 4.4$
$ = 1.2 \times {10^{23}}$ atoms.
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