MCQ
The odd numbers are divided as follows
$\begin{array}{*{20}{c}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1&3\end{array}$
$\begin{array}{*{20}{c}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5&7&9&{11}\end{array}$
$\begin{array}{*{20}{c}}{13}&{15}&{17}&{19}&{21}&{23}\\.&.&.&.&.&.\\.&.&.&.&.&.\\.&.&.&.&.&.\end{array}$
Then the sum of ${n^{th}}$ row is
- A${2^{n - 2}}[{2^n} + {2^{n - 1}} - 1]$
- B$\frac{1}{2}(2n + 1)$
- C$2n$
- ✓$4{n^3}$