The period of a simple pendulum measured inside a stationary lift is found to be $T$. If the lift starts accelerating upwards with acceleration of $g/3,$ then the time period of the pendulum is
  • A$\frac{T}{{\sqrt 3 }}$
  • B$\frac{T}{3}$
  • C$\frac{{\sqrt 3 }}{2}T$
  • D$\sqrt 3 \,T$
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