MCQ
The potential energy function for a particle executing linear simple harmonic motion is given by $U(x)=\frac{1}{2} k x^2$, where k is the force constant of the osicllator. For $k =0.5 Nm ^{-1}$, the graph U (x) versus x is shown in the figure given below.
Find out position of a particle carrying total energy 1 J moving under this potential at which it must turn back to its orignal position.
Find out position of a particle carrying total energy 1 J moving under this potential at which it must turn back to its orignal position.
- A$\pm 0.5 m$
- B$\pm 1 m$
- ✓$\pm 2 m$
- D$\pm 3 m$
