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Two condensers ${C_1}$and ${C_2}$ in a circuit are joined as shown in figure. The potential of point $A$ is ${V_1}$ and that of $B$ is ${V_2}$. The potential of point $D$ will be
The capacity of a parallel plate condenser is $10\,\mu \,F$, when the distance between its plates is $8 \,cm$. If the distance between the plates is reduced to $4\, cm$, then the capacity of this parallel plate condenser will be.........$\mu \,F$
$A$ $2$ $\mu F$ capacitor is charged to a potential $=$ $10\,V$. Another $4$ $\mu F$ capacitor is charged to a potential $=$ $20\,V$. The two capacitors are then connected in a single loop, with the positive plate of one connected with negative plate of the other. What heat is evolved in the circuit?......$\mu J$
If an electron moves from rest from a point at which potential is $50\, volt$ to another point at which potential is $70\, volt$, then its kinetic energy in the final state will be
Three capacitors $C_1,\,C_2$ and $C_3$ are connected as shown in the figure to a battery of $V\,volt$. If the capacitor $C_3$ breaks down electrically the change in total charge on the combination of capacitors is
The charge $q$ is fired towards another charged particle $Q$ which is fixed, with a speed $v$. It approaches $Q$ upto a closest distance $r$ and then returns. If $q$ were given a speed $2 v$, the closest distance of approach would be
In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be (Given area of plate $=A$ )
Three capacitors each of $4\,\,\mu F$ are to be connected in such a way that the effective capacitance is $6\,\,\mu F.$ This can be done by connecting thern