MCQ
The presence of carbon in an organic compound is detected by heating it with :
  • A
    Sodium metal to convert it to $\text{NaCN}.$
  • B
    $\text{CaO}$ to convert it into $\text{CO}$ which burns with a blue flame.
  • $\text{CuO}$ to convert it into $\mathrm{CO}_2$ which turns lime water milky.
  • D
    $\text{Cu}$ wire to give a bluish $-$ green flame.

Answer

Correct option: C.
$\text{CuO}$ to convert it into $\mathrm{CO}_2$ which turns lime water milky.
The given organic compound is mixed with dry copper oxide $\text{(CuO)}$ and heated in a hard glass tube. The products of the reaction are passed over $($white$)$ anhydrous copper sulphate and then bubbled through lime water.
If copper sulphate turns blue due to the formation of $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$
$($by water vapor$)$ then the compound contains hydrogen. If lime water is turned milky by $\mathrm{CO}_2$, then the compound contains carbon.

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