The ratio of the lengths of two wires $A$ and $B$ of same material is $1 : 2$ and the ratio of their diameter is $2 : 1.$ They are stretched by the same force, then the ratio of increase in length will be
A$2:1$
B$1:4$
C$1:8$
D$8:1$
Medium
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C$1:8$
c (c) $l = \frac{{FL}}{{AY}} \Rightarrow l \propto \frac{L}{{{d^2}}}$==>$\frac{{{l_1}}}{{{l_2}}} = \frac{{{L_1}}}{{{L_2}}} \times {\left( {\frac{{{d_2}}}{{{d_1}}}} \right)^2}$
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