$C: O=3: 4$
Mass ratio
$C : H : O =12: 3: 16$
Mole ratio
$C : H : O =1: 3: 1$
Empirical formula $= CH _{3} O$
Molecular formula $= C _{2} H _{6} O _{2}$
(saturated acyclic organic compound)
$C _{2} H _{6} O _{2}+\frac{5}{2} O _{2} \longrightarrow 2 CO _{2}+3 H _{2} O$
$2\, mole$ $5 \,mol$
Moles of $O _{2}$ required $=5$ moles
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Assertion $(A)$ : Boron is unable to form $BF _{6}^{3-}$
Reason $(R)$ : Size of $B$ is very small.
In the light of the above statements, choose the correct answer from the options given below.
