The ratio of two specific heats of gas ${C_p}/{C_v}$ for argon is $1.6$ and for hydrogen is $1.4$. Adiabatic elasticity of argon at pressure $P$ is $E.$ Adiabatic elasticity of hydrogen will also be equal to $E$ at the pressure
Diffcult
Download our app for free and get started
(b) Adiabatic elasticity $E = \gamma P$
For argon ${E_{Ar}} = 1.6\;P$….$(i)$
For hydrogen${E_{H2}} = 1.4P'$….$(ii)$
As elasticity of hydrogen and argon are equal
$1.6P = 1.4P'$ $⇒$ $P' = \frac{8}{7}P$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1If average depth of an ocean is $4000 \mathrm{~m}$ and the bulk modulus of water is $2 \times 10^9 \mathrm{Nm}^{-2}$, then fractional compression $\frac{\Delta V}{V}$ of water at the bottom of ocean is $\alpha \times 10^{-2}$. The value of $\alpha$ is ___________(Given, $\mathrm{g}=10 \mathrm{~ms}^{-2}, \rho=1000 \mathrm{~kg} \mathrm{~m}^{-3}$ )View Solution
- 2View SolutionThe modulus of elasticity is dimensionally equivalent to
- 3View SolutionShear modulus is zero for
- 4View SolutionThe following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied?
- 5Force constant of a spring $(K)$ is synonymous toView Solution
- 6What must be the lengths of steel and copper rods at $0^o C$ for the difference in their lengths to be $10\,cm$ at any common temperature? $(\alpha_{steel}=1.2 \times {10^{-5}} \;^o C^{-1})$ and $(\alpha_{copper} = 1.8 \times 10^{-5} \;^o C^{-1})$View Solution
- 7View SolutionWhich of the following relation is true ?
- 8View SolutionShearing stress causes change in
- 9An aluminium rod with Young's modulus $Y =7.0$ $\times 10^{10} N / m ^2$ undergoes elastic strain of $0.04 \%$. The energy per unit volume stored in the rod in SI unit is:View Solution
- 10An aluminum rod (Young's modulus $ = 7 \times {10^9}\,N/{m^2})$ has a breaking strain of $0.2\%$. The minimum cross-sectional area of the rod in order to support a load of ${10^4}$Newton's isView Solution