MCQ
The relation between root mean square speed $\left( v _{ rms }\right)$ and most probable speed $\left( v _{ p }\right)$ for the molar mass $M$ of oxygen gas molecule at the temperature of $300\, K$ will be
  • A
    $v _{ rms }=\sqrt{\frac{2}{3}} v _{ p }$
  • $v _{ rms }=\sqrt{\frac{3}{2}} v _{ p }$
  • C
    $v _{ rms }= v _{ p }$
  • D
    $v _{ rms }=\sqrt{\frac{1}{3}} v _{ p }$

Answer

Correct option: B.
$v _{ rms }=\sqrt{\frac{3}{2}} v _{ p }$
b
$v _{ rms }=\sqrt{\frac{3 RT }{ M }} \text { and } v _{ mp }=\sqrt{\frac{2 RT }{ M }}$

Thus $v _{ rms }=\sqrt{\frac{3}{2}} v _{ mp }$

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