The resistance of all the wires between any two adjacent dots is $R$. Then equivalent resistance between $A$ and $B$ as shown in figure is :
Diffcult
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As no current will pass through $\mathrm{CD}$, $CD$ arm assume to be open circuit.
$R_{1 A B}=\frac{\frac{7 R}{3} \times \frac{7 R}{3}}{\frac{7 R}{3}+\frac{7 R}{3}}=\frac{\frac{7 R}{3} \times \frac{7 R}{3}}{2 \times \frac{7 R}{3}}=\frac{7 R}{6}$
$R_{1 A B}=\frac{7 R}{6}$
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