MCQ
The r.m.s. speed of gas molecules is given by
- A$2.5\sqrt {\frac{{RT}}{M}} $
- ✓$1.73\sqrt {\frac{{RT}}{M}} $
- C$2.5\sqrt {\frac{M}{{RT}}} $
- D$1.73\sqrt {\frac{M}{{RT}}} $
✓
Answer
Correct option: B.
$1.73\sqrt {\frac{{RT}}{M}} $
b
${v_{rms}} = \sqrt {\frac{{3RT}}{M}} = \sqrt 3 \sqrt {\frac{{RT}}{M}} = 1.73\sqrt {\frac{{RT}}{M}} $
${v_{rms}} = \sqrt {\frac{{3RT}}{M}} = \sqrt 3 \sqrt {\frac{{RT}}{M}} = 1.73\sqrt {\frac{{RT}}{M}} $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Specific heats of monoatomic and diatomic gas is same than which relation is valid
If mass is written as $\mathrm{m}=\mathrm{kc}^{\mathrm{p}} \mathrm{G}^{-1 / 2} \mathrm{~h}^{1 / 2}$ then the value of $P$ will be : (Constants have their usual meaning with $\mathrm{k}$ a dimensionless constant)
→A student is performing the experiment of Resonance Column. The diameter of the column tube is $4$ $cm$. The frequency of the tuning fork is $512$ $Hz$. The air temperature is $38^o C$ in which the speed of sound is $336$ $m/s$. The zero of the meter scale coincides with the top end of the Resonance column tube. When the first resonance occurs, the reading of the water level in the column is ..... $cm$
→An object start sliding on a frictionless inclined plane and from same height another object start falling freely
A compass needle whose magnetic moment is $60 \,amp × m^2$ pointing geographical north at a certain place, where the horizontal component of earth's magnetic field is $40\, \mu Wb/m^2$, experiences a torque $1.2 \times {10^{ - 3}}\,N \times m.$ What is the declination at this place......$^o$
→In Young's double slit experiment, the phase difference between the light waves reaching third bright fringe from the central fringe will be ($\lambda$ $=6000 Å$ )
→In the circuit shown, the current in the $1\,\Omega$ resistor is
→In making an alloy, a substance of specific gravity ${s_1}$ and mass ${m_1}$ is mixed with another substance of specific gravity ${s_2}$ and mass ${m_2}$; then the specific gravity of the alloy is
→In the given figure, the value of $V_{0}$ will be $.....V$.
→Mercury does not wet glass, wood or iron because