The short wavelength limit for the Lyman series of the hydrogen spectrum is 913·4 $\mathring{\text{A}}$ Calculate the short wavelength limit for Balmer series of the hydrogen spectrum.
CBSE OUTSIDE DELHI - SET 2 2017
Download our app for free and get started
$\frac{1}{\lambda}=R\bigg(\frac{1}{n_1^{\text{ }\text{ }2}}-\frac{1}{n_2^{\text{ }\text{ }2}}\bigg)$
$\therefore $ For Balmer Series: $(\lambda_B)_{\text{short}|}=4/\text{R}$
and For Lyman Series: $(\lambda_L)_{\text{short}|}=1/\text{R}$
$\therefore {\lambda_{B}}=913.4\times4\mathring{\text{A}}=3653.6\mathring{\text{A}}$
$\therefore $ For Balmer Series: $(\lambda_B)_{\text{short}|}=4/\text{R}$
and For Lyman Series: $(\lambda_L)_{\text{short}|}=1/\text{R}$
$\therefore {\lambda_{B}}=913.4\times4\mathring{\text{A}}=3653.6\mathring{\text{A}}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Find the angular separation between the consecutive bright fringes in a Young's double slit experiment with blue-green light of wavelength 500nm. The separation between the slits is $2.0 × 10^{-3}$m.View Solution
- 2View SolutionIn a double-slit experiment the angular width of a fringe is found to be 0.2° on a screen placed 1 m away. The wavelength of light used is 600 nm. What will be the angular width of the fringe if the entire experimental apparatus is immersed in water? Take refractive index of water to be 4/3.
- 3In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of $\text{n}\lambda/\text{a}.$ Justify this by suitably dividing the slit to bring out the cancellation.View Solution
- 4An equilateral glass prism has a refractive index 1.6 in air. Calculate the angle of minimum deviation of the prism, when kept in a medium of refractive index $\frac{4\sqrt2}{5}.$View Solution
- 5A plate of thickness t made of a material of refractive index $\mu$ is placed in front of one of the slits in a double slit experiment.View Solution
- Find the change in the optical path due to introduction of the plate.
- What should be the minimum thickness t which will make the intensity at the centre of the fringe pattern zero? Wavelength of the light used is $\lambda$. Neglect any absorption of light in the plate.
- 6View SolutionWhen are two objects just resolved? Explain. How can the resolving power of a compound microscope be increased? Use relevant formula to support your answer.
- 7View SolutionAnswer the following question:
In a single slit diffraction experiment, the width of the slit is made double the original width. How does this affect the size and intensity of the central diffraction band? - 8White light is used in a Young's double slit experiment. Find the minimum order of the violet fringe $(\lambda=400\text{nm}),$ which overlaps with a red fringe $(\lambda=700\text{nm}).$View Solution
- 9View SolutionA transparent paper (refractive index = 1.45) of thickness 0.02mm is pasted on one of the slits of a Young's double slit experiment which uses monochromatic light of wavelength 620nm. How many fringes will cross through the centre if the paper is removed?
- 10The speed of the yellow light in a certain liquid is $2.4 \times 10^8 \mathrm{~m} / \mathrm{s}$. Find the refractive index of the liquid.View Solution