The sides of certain triangles are given below. Determine them are right triangles:
1.4cm, 4.8cm, 5cm.
1.4cm, 4.8cm, 5cm.
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For a given triangle to be a right angled, the sum of the squares of the two sides must be equal to the square of the largest side.
Let a = 1.4cm, b = 4.8cm, and c = 5cm
$\big(\text{a}^2+\text{b}^2\big)=\big[(1.4)^2+(4.8)^2\big]\text{cm}^2$
$=(1.96+23.04)\text{cm}^2=25\text{cm}^2$
$\text{c}^2=(5\text{cm)}^2=25\text{cm}^2$
$\therefore\big(\text{a}^2+\text{b}^{2}\big)=\text{c}^2$
Hence, the given triangle is a right triangle.
Let a = 1.4cm, b = 4.8cm, and c = 5cm
$\big(\text{a}^2+\text{b}^2\big)=\big[(1.4)^2+(4.8)^2\big]\text{cm}^2$
$=(1.96+23.04)\text{cm}^2=25\text{cm}^2$
$\text{c}^2=(5\text{cm)}^2=25\text{cm}^2$
$\therefore\big(\text{a}^2+\text{b}^{2}\big)=\text{c}^2$
Hence, the given triangle is a right triangle.
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