The sides of certain triangles are given below. Determine them are right triangles:
1.6cm, 3.8cm, 4cm.
1.6cm, 3.8cm, 4cm.
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For a given triangle to be a right angled, the sum of the squares of the two sides must be equal to the square of the largest side.
let a = 1.6cm, b = 3.8cm and c = 4cm
$\big(\text{a}^2+\text{b}^2\big)=\big[(1.6)^2+{(3.8})^2\big]\text{cm}^2$
$=(2.56+14.44)\text{cm}^2=17\text{cm}^2$
$\text{c}^2=(4)^2=16\text{cm}^2$
$\therefore\big(\text{a}^2+\text{b}^2\big)\not=\text{c}^2$
Hence, the given triangle is a right triangle.
let a = 1.6cm, b = 3.8cm and c = 4cm
$\big(\text{a}^2+\text{b}^2\big)=\big[(1.6)^2+{(3.8})^2\big]\text{cm}^2$
$=(2.56+14.44)\text{cm}^2=17\text{cm}^2$
$\text{c}^2=(4)^2=16\text{cm}^2$
$\therefore\big(\text{a}^2+\text{b}^2\big)\not=\text{c}^2$
Hence, the given triangle is a right triangle.
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AD = (7x - 4)cm, AE = (5x - 2)cm, DB = (3x + 4)cm and EC = 3x cm.
