The sides of certain triangles are given below. Determine them are right triangles:
9cm, 16cm, 18cm.
9cm, 16cm, 18cm.
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For a given triangle to be a right angled, the sum of the squares of the two sides must be equal to the square of the largest side.
Let a = 9cm, b = 16cm and c= 18cm. Then
$\Big(\text{a}^2+\text{b}^2\Big)=\Big[9^2+(16)^2\Big]$
$=(81+256)\text{cm}^2$
$=337\text{cm}^2$
and $\text{c}^2=(18)^2\text{cm}^2=324\text{cm}^2$
$\therefore\big(\text{a}^2+\text{b}^2\big)\not=\text{c}^2$
Hence the given triangle is not right angled.
Let a = 9cm, b = 16cm and c= 18cm. Then
$\Big(\text{a}^2+\text{b}^2\Big)=\Big[9^2+(16)^2\Big]$
$=(81+256)\text{cm}^2$
$=337\text{cm}^2$
and $\text{c}^2=(18)^2\text{cm}^2=324\text{cm}^2$
$\therefore\big(\text{a}^2+\text{b}^2\big)\not=\text{c}^2$
Hence the given triangle is not right angled.
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