If the r.m.s. speed of chlorine molecule is $490\,m / s$ at $27^{\circ}\,C$, the r.m.s. speed of argon molecules at the same temperature will be $......\,m/s$ (Atomic mass of argon $=39.9\,u$, molecular mass of chlorine $=70.9\,u )$
A$751.7$
B$451.7$
C$651.7$
D$551.7$
JEE MAIN 2023, Easy
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C$651.7$
c $V _{ rms }=\sqrt{\frac{3 RT }{ M }} \quad \frac{ v _{ Ar }}{ v _{ Cl }}=\sqrt{\frac{ M _{ Cl }}{ M _{ Ar }}}$
$\Rightarrow v _{ Ar }=1.33 \times 490=651.7\,m / s$
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