The temperature of a liquid drops from $365K$ to $361 K$ in $2$ minutes. Find the time during which temperature of the liquid drops from $344\;K$ to $342K$. Temperature of room is $293\;K$ ....... $\sec$
Diffcult
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Two bottles $A$ and $B$ have radii $R_{A}$ and $R_{B}$ and heights $h_{A}$ and $h_{B}$ respectively, with $R_{B}=2 R_{A}$ and $h_{B}=2 h_{A}$. These are filled with hot water at $60^{\circ} C$. Consider that heat loss for the bottles takes place only from side surfaces. If the time, the water takes to cool down to $50^{\circ} C$ is $t_{A}$ and $t_{B}$ for bottles $A$ and $B$, respectively. Then, $t_{A}$ and $t_{B}$ are best related asView Solution
- 2Which of the following is the $\nu_m = T$ graph for a perfectly black body ($\nu_m$ =maximum frequency of radiation)View Solution
- 3There are two identical vessels filled with equal amounts of ice. The vessels are of different metals., If the ice melts in the two vessels in $20$ and $35$ minutes respectively, the ratio of the coefficients of thermal conductivity of the two metals isView Solution
- 4View SolutionIf a black body is heated at a high temperature, it seems to be
- 5The energy emitted per second by a black body at ${27^o}C$ is $10\;J$. If the temperature of the black body is increased to ${327^o}C$, the energy emitted per second will be ......... $J$View Solution
- 6Two spherical black bodies of radii ${r_1}$ and ${r_2}$ and with surface temperature ${T_1}$and ${T_2}$ respectively radiate the same power. Then the ratio of ${r_1}$ and ${r_2}$ will beView Solution
- 7View SolutionHeat current is maximum in which of the following (rods are of identical dimension)
- 8The top of insulated cylindrical container is covered by a disc having emissivity $0.6$ and thickness $1\, cm$. The temperature is maintained by circulating oil as shown in figure. If temperature of upper surface of disc is $127^o C$ and temperature of surrounding is $27^o C$, then the radiation loss to the surroundings will be (Take $\sigma = \frac{{17}}{3} \times {10^{ - 8}}W/{m^2}{K^4})$View Solution
- 9Calculate the surface temperature of the planet, if the energy radiated by unit area in unit time is $5.67\times10^4\, watt$ : (Planet may be assumed to black body)View Solution
- 10View SolutionThe Wien’s displacement law express relation between