The temperature of sink of Carnot engine is {27^o}C. Efficiency of engine is 25%. Then temperature of source is ...... ^oC

Q: The temperature of sink of Carnot engine is ${27^o}C$. Efficiency of engine is $25\%.$ Then temperature of source is ...... $^oC$

c (c) $\eta = 1 - \frac{{{T_2}}}{{{T_1}}}$ ==> $\frac{{25}}{{100}} = 1 - \frac{{300}}{{{T_1}}}$ ==> $\frac{1}{4} = 1 - \frac{{300}}{{{T_1}}}$ ${T_1} = 400\,K = 127^\circ C$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

The temperature of sink of Carnot engine is ${27^o}C$. Efficiency of engine is $25\%.$ Then temperature of source is ...... $^oC$

A$227$
B$327$
C$127$
D$27$

Medium

STD 11 Science
NEET
STD 11 - 11. thermodynamics
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free