An ideal heat engine exhausting heat at $77\,^oC$. To have a $30\%$ efficiency. It must take heat at...... $^oC$
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$\eta=1-\frac{\mathrm{T}_{\mathrm{L}}}{\mathrm{T}_{\mathrm{H}}} \Rightarrow \frac{30}{100}=1-\frac{350}{\mathrm{T}_{\mathrm{H}}}$
$\Rightarrow \mathrm{T}_{\mathrm{H}}=500 \mathrm{K}$
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