A particle executes $SHM$ of amplitude $25\, cm$ and time period $3\, s$. What is the minimum time required for the particle to move between two points $12.5\, cm$ on either side of the mean position ..... $\sec$
AIIMS 2010, Medium
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$y=r \sin \omega t$
$12.5=25 \sin \frac{2 \pi}{3} \times t \quad\left(\because \omega=\frac{2 \pi}{\mathrm{T}}\right)$
$\frac{\pi}{6}=\frac{2 \pi}{3} t$
$t=\frac{1}{4} \sec =0.25 \mathrm{sec}$
$t^{\prime}=2 t$
$=2 \times 0.25=0.5 \mathrm{sec}$
for either side
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