MCQ
The total energy of a particle, executing simple harmonic motion is
- A$ \propto x$
- B$ \propto {x^2}$
- ✓Independent of$x$
- D$ \propto {x^{1/2}}$
✓
Answer
Correct option: C.
Independent of$x$
c
(c)Total energy $ = \frac{1}{2}m{\omega ^2}{a^2}$= constant
(c)Total energy $ = \frac{1}{2}m{\omega ^2}{a^2}$= constant
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