MCQ
The total number of electrons present in $18\,ml$ water (density $= 1\,g/ml$) is
- A$6.023 \times 10^{23}$
- ✓$6.023 \times 10^{24}$
- C$6.023 \times 10^{25}$
- D$6.023 \times 10^{21}$
✓
Answer
Correct option: B.
$6.023 \times 10^{24}$
b
The total number of electrons present in $18 \mathrm{ml}$ of water is $6.023 \times 10^{24}$.
The total number of electrons present in $18 \mathrm{ml}$ of water is $6.023 \times 10^{24}$.
Number of electron in one molecule of $H_{2} O$ is $2+8=10$.
Density $=1 g / m l$
$\therefore 18 \mathrm{ml}$ means $18 \mathrm{g}$
Moles $=\frac{18}{18}=1$
Molecules $=6.023 \times 10^{23}$
Electrons $=6.023 \times 10^{23} \times 10=6.023 \times 10^{24}$
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