The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is 1 k Omega. The

Q: The transfer ratio of a transistor is $50.$ The input resistance of the transistor when used in the common-emitter configuration is $1 k \Omega$. The peak value for an A.C input voltage of $0.01 V$ peak is

$\beta=50, R=1000 \Omega, V=0.01 \mathrm{~V} $ $ \beta=\frac{i_c}{i_b} \text { and } i_b=\frac{V_i}{R_i}=\frac{0.01}{10^3}=10^{-5}\mathrm{~A}$ Hence $i_c=50 \times 10^{-5} \mathrm{~A}=500 \mu \mathrm{A}$.

MCQ

CBSE - English Medium

The transfer ratio of a transistor is $50.$ The input resistance of the transistor when used in the common-emitter configuration is $1 k \Omega$. The peak value for an A.C input voltage of $0.01 V$ peak is

A$100 \mu A$
B$0.01 mA$
C$0.25 mA$
D$500 \mu A$

STD 12 Science
JEE physics
Electronics
NCERT

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