where $x$ and $y$ are in $m$ and $t$ is in $s$. The length of the string is $1.5\, m$ and its mass is $3.0 \times 10^{-2} \,kg$, then tension in string is ..... $N$
$\therefore \mathrm{v}=\frac{120 \pi}{2 \pi / 3}=180 \mathrm{\,m} / \mathrm{s}$
$\mathrm{T}=\mathrm{v}^{2} \mu=180 \times 180 \times \frac{3 \times 10^{-2}}{1.5}=648 \mathrm{\,N}$