The two plates $X $ and $Y$ of a parallel plate capacitor of capacitance $C$ are given a charge of amount $Q$ each. $X$ is now joined to the positive terminal and $Y$ to the negative terminal of a cell of $emf$ $E = Q/C$.
Diffcult
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As the emf of cell is $\epsilon=Q / C,$ charge of amount $Q$ will flow from the positive terminal
to the negative terminal of the cell through the capacitor.
As the $Y$ is connected to negative terminal of cell so it is ground and the total charge on plate $Y$ will be zero.
Here cell charge the capacitor plate $\mathrm{X}$ and its total charge $=(Q+Q)=2 Q$
The energy will supply by cell is $U=\frac{1}{2} C \epsilon^{2}$
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