The wavelength of maximum energy released during an atomic explosion was $2.93 \times {10^{ - 10}}m$. Given that Wein's constant is $2.93 \times {10^{ - 3}}m - K$, the maximum temperature attained must be of the order of
AIIMS 2010, Medium
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(b)$\therefore \;T = \frac{b}{{{\lambda _m}}} = \frac{{2.93 \times {{10}^{ - 3}}}}{{2.93 \times {{10}^{ - 10}}}} = {10^7}\;K$
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