Question
The weight of a body on the surface of earth is 250N. Calculate its weight at distance equal to half of the radius of earth below the surface of earth. (Radius of earth = 6400km).

Answer

Given: W = mg = 250N $\text{d}=\frac{6400}{2}=3200\text{km}$ $\text{R}=6400\text{km}$ $\text{W}'=\text{mg}'=?$ $\text{g}'=\text{g}\Big(1-\frac{\text{d}}{\text{R}}\Big)$ $\text{mg}'=\text{mg}\Big(1-\frac{\text{d}}{\text{R}}\Big)$ $\text{W}'=250\Big(1-\frac{3200}{6400}\Big)$ $=250\Big(1-\frac{1}{2}\Big)=125\text{N}.$

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