Download App
The weight of an aeroplane flying in air is balanced by
Easy
Download our app for free and get startedPlay store
(b) Upper surface of wing is more curved than its lower surface, therefore, the speed of air above the wings is larger than the speed of the air below the wings. According to Bernoulli's theorem, the pressure above the wings becomes less than the pressure below the wings. Due to this difference of pressure on the two sides of the wings, a vertical lift acts on the aeroplane. When this lift is sufficient to overcome the gravity pull on the aeroplane, the aeroplane is lifted up.
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Download App

Similar Questions

  • 1
    A small hole of area of cross-section $2\; \mathrm{mm}^{2}$ is present near the bottom of a fully filled open tank of height $2\; \mathrm{m} .$ Taking $\mathrm{g}=10 \;\mathrm{m} / \mathrm{s}^{2},$ the rate of flow of water through the open hole would be nearly ......... $\times 10^{-6} \;m^{3} /s$
    View Solution
  • 2
    Air is streaming past a horizontal air plane wing such that its speed in $ 120 m/s$  over the upper surface and $ 90 m/s$  at the lower surface. If the density of air is $1.3 kg$  per $metre^3 $ and the wing is $10 m $ long and has an average width of $2 m$, then the difference of the pressure on the two sides of the wing of ....... $Pascal$ 
    View Solution
  • 3
    A vessel of area of cross-section A has liquid to a height $H$ . There is a hole at the bottom of vessel having area of cross-section a. The time taken to decrease the level from ${H_1}$ to ${H_2}$ will be
    View Solution
  • 4
    The bulk modulus of a liquid is $3 \times 10^{10}\, Nm ^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is  ........ $\times 10^{8}\; Nm ^{-2}$
    View Solution
  • 5
    Different physical quantities are given in Column - $\mathrm{I}$ and their dimensional formula are given in Column - $\mathrm{II}$. Match them appropriately.
    Column - $\mathrm{I}$ Column - $\mathrm{II}$
    $(a)$ Viscous force $(i)$ $\left[ {{M^1}{L^1}{T^{ - 2}}} \right]$
    $(b)$ Coefficient of viscosity $(ii)$ $\left[ {{M^1}{L^{ - 1}}{T^{ - 1}}} \right]$
      $(iii)$ $\left[ {{M^1}{L^{ - 1}}{T^{ - 2}}} \right]$
    View Solution
  • 6
    An inverted tube barometer is kept on a lift  with a moving downward with a deceleration $\alpha $ . The density of mercury is $\rho$ and acceleration due to gravity is $g$ . If the atmospheric pressure be $P_0$ then
    View Solution
  • 7
    The density of the atmosphere is $1.29\, kg/m^3$, then how high would the atmosphere extend ? $(g = 9.81\, m/sec^2)$ ........ $km$
    View Solution
  • 8
    A sample of metal weighs $210 gm$  in air, $180 gm$  in water and $120 gm$  in liquid. Then relative density $(RD) $ of
    View Solution
  • 9
    Small water droplets of radius $0.01 \mathrm{~mm}$ are formed in the upper atmosphere and falling with a terminal velocity of $10 \mathrm{~cm} / \mathrm{s}$. Due to condensation, if $8 \mathrm{such}$ droplets are coalesced and formed a larger drop, the new terminal velocity will be ........... $\mathrm{cm} / \mathrm{s}$.
    View Solution
  • 10
    A plane is in level flight at constant speed and each of its two wings has an area of $40 \mathrm{~m}^2$. If the speed of the air is $180 \mathrm{~km} / \mathrm{h}$ over the lower wing surface and $252 \mathrm{~km} / \mathrm{h}$ over the upper wing surface, the mass of the plane is______ $\mathrm{kg}$. (Take air density to be $1 \mathrm{~kg} \mathrm{~m}^{-3}$ and $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )
    View Solution