The work of $146\ kJ$ is performed in order to compress one kilo mole of gas adiabatically and in this process the temperature of the gas increases by $7^o C$. The gas is $(R=8.3\ J\ mol^{-1} K^{-1})$
AIEEE 2006, Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1During an experiment, an ideal gas is found to obey a condition $VP^2 =$ constant. The gas is initially at a temperature $T$, pressure $P$ and volume $V.$ The gas expands to volume $4V$.View Solution
- 2View SolutionFirst law of thermodynamics is a special case of
- 3In changing the state of thermodynamics from $A$ to $B$ state, the heat required is $Q$ and the work done by the system is $W.$ The change in its internal energy isView Solution
- 4$1c{m^3}$ of water at its boiling point absorbs $540$ calories of heat to become steam with a volume of $1671c{m^3}$.If the atmospheric pressure = $1.013 \times {10^5}N/{m^2}$ and the mechanical equivalent of heat = $4.19J/calorie$, the energy spent in this process in overcoming intermolecular forces is ..... $cal$View Solution
- 5Work done by a system under isothermal change from a volume ${V_1}$ to ${V_2}$ for a gas which obeys Vander Waal's equation $(V - \beta n)\,\left( {P + \frac{{\alpha {n^2}}}{V}} \right) = nRT$View Solution
- 6View SolutionIn adiabatic expansion of a gas
- 7Consider the following volume-temperature $( V - T )$ diagram for the expansion of $5$ moles of an ideal monoatomic gas.View Solution
Considering only $P-V$ work is involved, the total change in enthalpy (in Joule) for the transformation of state in the sequence $X \rightarrow Y \rightarrow Z$ is $\qquad$
[Use the given data: Molar heat capacity of the gas for the given temperature range, $C _{ v , m }=12 J K ^{-1} mol ^{-1}$ and gas constant, $R =8.3 J K ^{-1} mol ^{-1}$ ]
- 8An ideal gas heat engine operates in Carnot cycle between $227°C$ and $127°C.$ It absorbs $6 \times {10^4}$ cals of heat at higher temperature. Amount of heat converted to work is .........$ \times {10^4}\; cal$View Solution
- 9The latent heat of vaporization of water is $2240 \,J/gm$. If the work done in the process of vaporization of $1\, gm$ is $168\, J$, then increase in internal energy is .... $J$View Solution
- 10View SolutionIn an isothermal expansion