Three capillaries of length $L, \frac{L}{2}$ and $\frac{L}{3}$ are connected in series. Their radii are $r, \frac{r}{2}$ and $\frac{r}{3}$ respectively. Then if stream-line flow is to be maintained and the pressure across the first capillary is $P$, then ............
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(a)
$\because$ Rate of flow will be same across all pipes
So, pressure across the pipe $\propto \frac{\text { length }}{(\text { radius })^4}$ $\quad \quad\{$ rate of flow of liquid (Q) $Q=\frac{\pi P r^4}{8 \eta L}$
$\frac{P_1}{P_2}=\frac{\left(L / r^4\right)}{\left(\frac{L / 2}{(r / 2)^4}\right)}=\frac{1}{8}$
Then $P_2=8 P_1$
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