Under a pressure head the rate of orderly volume flow of a liquid through a capillary tube is $Q$ . If the length of capillary tube is doubled and the diameter of tube is halved, the rate of flow would become
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$\mathrm{Q}=\frac{\pi \mathrm{Pr}^{4}}{8 \mathrm{n} \ell}$
$\frac{Q^{\prime}}{Q}=\left(\frac{r_{2}}{r_{1}}\right)^{4}\left(\frac{\ell_{1}}{\ell_{2}}\right)$
$Q^{\prime}=\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{4} Q=\frac{Q}{32}$
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