Three long current carrying wires $P, Q$ and $R$ placed perpendicular to plane of the paper. Magnetic force per unit length on wire $'R'$ is
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$F_{net }=F_{Q}-F_{p}=\frac{\mu_{0}(4)(2)}{2 \pi(1)}-\frac{\mu_{0}(1)(2)}{2 \pi(3)}$$=\frac{44}{3} \times 10^{-7} \,\mathrm{N} / \mathrm{m}$
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