Question
Three long, straight parallel wires carrying current, are arranged as shown in figure. The force experienced by a $25\, cm$ length of wire $C$ is
✓
Answer
(c) Force on wire $C$ due to wire $D$
${F_D} = {10^{ - 7}} \times \frac{{2 \times 30 \times 10}}{{2 \times {{10}^{ - 2}}}} \times 25 \times {10^{ - 2}} = 5 \times {10^{ - 4}}\,N$
(towards right)
Force on wire $C$ due to wire $G$
${F_G} = {10^{ - 7}} \times \frac{{2 \times 20 \times 10}}{{2 \times {{10}^{ - 2}}}} \times 25 \times {10^{ - 2}} = 5 \times {10^{ - 4}}\,N$
(towards left)
$==>$ Net force on wire C is ${F_{net}} = {F_D} - {F_G} = 0$
${F_D} = {10^{ - 7}} \times \frac{{2 \times 30 \times 10}}{{2 \times {{10}^{ - 2}}}} \times 25 \times {10^{ - 2}} = 5 \times {10^{ - 4}}\,N$
(towards right)
Force on wire $C$ due to wire $G$
${F_G} = {10^{ - 7}} \times \frac{{2 \times 20 \times 10}}{{2 \times {{10}^{ - 2}}}} \times 25 \times {10^{ - 2}} = 5 \times {10^{ - 4}}\,N$
(towards left)
$==>$ Net force on wire C is ${F_{net}} = {F_D} - {F_G} = 0$
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