A capacitor of capacitance $6\,\mu \,F$ is charged upto $100$ $volt$. The energy stored in the capacitor is........$Joule$
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(c) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 6 \times {10^{ - 6}}{(100)^2} = 0.03\,J$
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