MCQ
To an ideal triatomic gas $800 \,cal$ heat energy is given at constant pressure. If vibrational mode is neglected, then energy used by gas in work done against surroundings is ......... $cal$
  • $200$
  • B
    $300$
  • C
    $400$
  • D
    $60$

Answer

Correct option: A.
$200$
a
(a)

Heat at constant pressure

$\Delta Q=n C_p \Delta T$

Heat for doing work

$\Delta W=n R \Delta T$

Then $\frac{\Delta W}{\Delta Q}=\frac{n R \Delta T}{n C_P \Delta T}$

$\frac{\Delta W}{800}=\left(\frac{\gamma-1}{\gamma}\right)$

$\frac{\Delta W}{800}=1-\frac{1}{\gamma}$

$\frac{\Delta W}{800}=1-\frac{3}{4}$

$\Delta W=200 \,cal$

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