Height of the mercury column, \(h_{1}=0.76 m\)

Density of French wine, \(\rho_{2}=984 kg / m ^{3}\)

Height of the French wine column \(=h_{2}\)

Acceleration due to gravity, \(g=9.8 m / s ^{2}\)

The pressure in both the columns is equal, i.e.,

Pressure in the mercury column

\(=\) Pressure in the French wine column

\(\rho_{1} h_{1} g =\rho_{2} h_{2} g\)

\(h_{2}=\frac{\rho_{1} h_{1}}{\rho_{2}}\)

\(=\frac{13.6 \times 10^{3} \times 0.76}{984}\)
\(=10.5 m\)
Hence, the height of the French wine column for normal atmospheric pressure is \(10.5\; m\)